x^2-28x+195=0

Solution for x^2-28x+195=0 equation:

x^2-28x+195=0

a = 1; b = -28; c = +195;
Δ = b2-4ac
Δ = -282-4·1·195
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2}{2*1}=\frac{26}{2}
=13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2}{2*1}=\frac{30}{2}
=15
$